[MLUG] grepping the 9th line after a matching line

[Mike Miller <EMAIL:PROTECTED>]

You guys have been absolutely amazing on that list question about copying 
files.  So now I have another question:

Here's a fun problem -- suppose I want to grab the 9th line following a 
line that matches a pattern.  I think perl may be good for this -- I'm 
pretty sure I can do it as a one-liner.  But there are "-A" and "-B" 
options in the GNU version of egrep that simplify this a little.  The "B" 
and "A" stand for "before" and "after."  So...

egrep -A9 [pattern] file

...grabs the matching lines and 9 subsequent lines for each match.  The 
problem is that I don't want the first 8 lines from each match. 
Fortunately, egrep -A gives me a line between each set of 9 that matches 
the following regexp pattern:  ^--$  That is, it is a single line 
consisting of nothing but two hyphens.  So this gives me the 9th line 
following each match but with that darned pair of hyphens still there...

egrep -A9 [pattern] file | egrep -B1 '^--$'

...so I grep out the extra hyphen lines:

egrep -A9 [pattern] file | egrep -B1 '^--$' | egrep -v '^--$'

That's fairly straightforward but there is one more annoying problem: 
The last line is not followed by the ^--$ regular expression, so it is 
lost.  Well, then I can do this but this is getting rather long:

( egrep -A9 [pattern] file | egrep -B1 '^--$' | egrep -v '^--$' ; egrep -A9 [pattern] file | tail -1 )

Long, but it works except under conditions where the sets of 9 lines 
overlap!  Then it totally screws up.  Luckily, that condition does not 
arise in my application, so I'm fine with this.

Question:  Is there a better way?

Mike

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