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Mike Miller wrote:
> I can do this:
>
> perl -e
> '($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)=localtime(time);
> print "$mon $mday $year\n";' | awk '{print $1+1"/"$2"/"$3+1900}'
>
> using awk to format the date properly. I'll bet I just need to know how
> to write the perl print statement correctly in the first place, then I can
> skip the awk. Can anyone tell me how?
How about this:
perl -e
'($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)=localtime(time);
print $mon+1," $mday ",$year+1900,"\n";'
-- MK
<< Terra es et in terram ibis >>
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