Home | FAQ | Server | Presentations | Mailing Lists/Archives | Member Tools | Links | Sponsors | ContactHome | FAQ | Server | Presentations | Mailing Lists/Archives | Member Tools | Links | Sponsors | ContactOn Wed, 5 Jan 2000, Christopher J. Kaiser wrote: > Nope. As per above: $a = -98, $b = 100. Since $b is positive, rule one > applies. Therefore, $a % $b = %a - $b * x, where $b * x < $a. Thus, x > = -2, $b * x = -200, and $a % $b = -98 - (-200) = 2. I think you meant to say that x = -1, and -98 - (-100) = 2. Mike