Re: [MLUG - DISCUSSION] Re: [4, 3]*sqrt(X/12)

["Ryan Thornton" <EMAIL:PROTECTED>]

I was thinking monitor dimensions so I was close :)

Actually for digital cameras, all are not 4:3 -- it depends a lot on
the CMOS sensor.  (3:2 being popular)

• 3008 x 2000 (Large, 6 MP)
• 2256 x 1496 (Medium, 3.4 MP)
• 1504 x 1000 (Small, 1.5 MP)

A good place to spend time looking at lots of specifications:
www.dpreview.com

-- Ryan

On 5/8/07, Mike Miller <EMAIL:PROTECTED> wrote:
> On Fri, 4 May 2007, Mike Miller wrote:
>
> > Just thought you all would quickly figure out the value in this
> > equation:
> >
> > Y = [4, 3]*sqrt(X/12)
> >
> > That's a vector times a scalar.  Or, equivalently...
> >
> > Y = [4*sqrt(X/12), 3*sqrt(X/12)]
> >
> > So the quiz of the day is this:  What is X and what is Y and what does
> > this have to do with computers?
>
>
> OK, no one had a suggestion.  This is about "megapixels" and digital
> cameras.  Someone says that they have a 2.1 megapixel camera, but what are
> the dimensions?  Well, divide 2.1 million by twelve, take the square root
> and multiply the answer by four to get the width and by 3 to get the
> height.  When I read about a 7.1 megapixel camera, I wanted to know the
> dimensions, but they weren't listed.  Using the formula just described I
> got these dimensions:
>
> 3076.8  2307.6
>
> So I guessed it was really 3*(1024 x 768) = 3072 x 2304
>
> Which seems to be correct.
>
> Mike
>
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