[MLUG - DISCUSSION] Re: [4, 3]*sqrt(X/12)

[Mike Miller <EMAIL:PROTECTED>]

On Fri, 4 May 2007, Mike Miller wrote:

> Just thought you all would quickly figure out the value in this 
> equation:
>
> Y = [4, 3]*sqrt(X/12)
>
> That's a vector times a scalar.  Or, equivalently...
>
> Y = [4*sqrt(X/12), 3*sqrt(X/12)]
>
> So the quiz of the day is this:  What is X and what is Y and what does 
> this have to do with computers?


OK, no one had a suggestion.  This is about "megapixels" and digital 
cameras.  Someone says that they have a 2.1 megapixel camera, but what are 
the dimensions?  Well, divide 2.1 million by twelve, take the square root 
and multiply the answer by four to get the width and by 3 to get the 
height.  When I read about a 7.1 megapixel camera, I wanted to know the 
dimensions, but they weren't listed.  Using the formula just described I 
got these dimensions:

3076.8  2307.6

So I guessed it was really 3*(1024 x 768) = 3072 x 2304

Which seems to be correct.

Mike

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